Impossible to change a volume measure to a length measure
It depends, can you change the width and the length??
It is quadrupled.
Your question is a bit difficult to understand. Of course, if the box surface area is doubled, then the box is bigger. I suppose two valid questions are, if the sides are all increased by the same factor, what is this factor, and a second question is what is the new volume as compared to the initial one. If we look at the front face of the box, the area is height x width or A= H X W. So, if our length and with are multiplied by some factor, I will call X, to double the area, we have 2 A = H * X * W *X or X2*H*W =2A and if I substitute L*W for A, and cancel the A on each side, X2 = 2 or X = sqrt of 2. The same calculation can be made for the sides of the box, and you will see the factor is square root of 2 or 1.414. Now the second question is how much does the volume change. Since each side is larger by 1.414 and volume equals Height * width * depth, the volume increase by Factor = (2 1/2)3 = 2 3/2 or 2*sqrt(2) = 2*1.414 = 2.828 The box with double the surface area will have 2.828 more volume.
The volume of a cube is the side cubed, so a cube with a side length of 4 has a volume of 43 = 64.
if all 3 dimensions increase b factor of 7 then volume changes by 7 cubed or a factor of 343
The volume is increased by a factor of 23 = 8.
Side = 3 units, volume = 27 cu units, side = 6 units, volume = 216 cu units. The side is increased by a factor of 2 and the volume is increased by a factor of 8, ie 23 If the side were increased by a factor of 3, we would thus expect the volume to increase by a factor of 33 ie 27, so: side 9 units, volume 729 cu units which is indeed 27 x 27. To summarise: the volume increases by the cube of the factor by which the side increases.
Either the volume or the pressure of the gas will increase.
When linear dimensions are increased by a factor of 'N', area increasesby the factor of N2 and volume increases by the factor of N3.(1.10)3 = 1.331 = 33.1% increase
300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:
8... apex :)
64! -Apex
Well the scale factor for it needs to be like more adjectives so it has to be Lake the answer is a
(3)3 = 27
64
If the total volume increases, then the pressure decreases.