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300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:

Q: A cardboard box has a length of 3 feet height of 2 feet and depth of 2 feet If the length and depth are doubled by what percent does the volume of the box change?

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A 3-Dimensional box's volume will double for each dimension that is doubled. i.e. if just the height, length or depth are doubled, the volume increases 200%, if 2 of those dimensions are doubled the volume increases by 400%. if all 3 are double the volume increases by 800%.

If the base stays the same, the area is also doubled.

When you change the linear size it changes the areas by the square and the volume of the cube.

As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.

volume is related as radius squared x height soif both radius and height doubled volume increases 2 x 2 x 2 = 8 times

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A 3-Dimensional box's volume will double for each dimension that is doubled. i.e. if just the height, length or depth are doubled, the volume increases 200%, if 2 of those dimensions are doubled the volume increases by 400%. if all 3 are double the volume increases by 800%.

The volume will be doubled.

A box of those dimensions would have a volume of 3 x 2 x 2 or 12 cubic feet. If the length is doubled to 6 feet, the depth is doubled to 4 feet and the height remains the same at 2 feet, the volume would then be: 6 x 4 x 2 or 48 cubic feet. The percent change of the increase would be the difference in the volumes, divided by the original volume, multiplied by 100. In this example, the percent increase is 36/12 times 100 or 300%.

If the base stays the same, the area is also doubled.

The area of the triangle would double

if length and width are doubled then the volume should mulitiply by 8

It is quadrupled.

When you change the linear size it changes the areas by the square and the volume of the cube.

The area is multiplied by 4, not doubled.

As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.

The area gets doubled.

In the first case, the area will remain the same. In the second case, the area will doubled.