to find x in that way you need to have two measurements not just one
x - 11 degrees, where x is the measure of the angle you started with.
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
X=30 degrees
Let x be the measure of the base angle in degrees, so the measure of the vertex angle in degrees it will be x + 15. Since the triangle is an isosceles triangle, where the base angles are congruent, we can form the equation: 2x + (x + 15) = 180 3x + 15 = 180 subtract 15 to both sides; 3x = 165 divide by 3 to both sides; x = 55 x + 15 = 55 + 15 = 70 Thus, each base angle is 55° and the vertex angle is 70°.
The sum of the measures of the angles of a triangle is 180 degrees. First, calculate the sum of the two known angles. Then subtract that result from 180. That difference is the measure of the third unknown angle. Given: One angle of a triangle is 15 degrees and the second angle of the triangle is 85 degrees. To find: We need to find the third angle of the triangle. Let the third angle of the triangle be x. We know that the sum of the angles in a triangle is 180 degrees. ==> 15 degrees + 85 degrees + x degrees = 180 degrees. ==> 100 degrees + x degrees = 180 degress. ==> x = 180 degrees - 100 degrees. ==> x = 80 degress. Therefore the third angle of the triangle is 80 degrees.
x - 11 degrees, where x is the measure of the angle you started with.
Suppose angle is X degrees. Then X + 73 = 180 degrees so that X = 107 degrees.
the answer is 68 degrees
Suppose the angle is x degrees. Then its supplement is 180 - x So 180 - x = x - 44 224 = 2x so x = 112 degrees.
16.5 degrees
It depends on what x is.
Suppose the measure of the angle is x then its supplement is 180 - x x = 180 - x + 30 = 210 - x 2x = 210 => x = 105 degrees (supplementary angle = 75)
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.
supplement + angle = 180180 - angle = supplementangle = supplement + 40 = 180 - angle +40 = 220-angle2 x angle = 220angle = 110 degrees
X=30 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.