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Let x be the measure of the base angle in degrees, so the measure of the vertex angle in degrees it will be x + 15. Since the triangle is an isosceles triangle, where the base angles are congruent, we can form the equation:

2x + (x + 15) = 180

3x + 15 = 180 subtract 15 to both sides;

3x = 165 divide by 3 to both sides;

x = 55

x + 15 = 55 + 15 = 70

Thus, each base angle is 55° and the vertex angle is 70°.

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Q: The measure of the vertex angle of an isosceles triangle is 15 degrees more than the measure of each base angle. Find the number of degrees in each angle of the triangle.?
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To figure out what the measure of the base angles in an isosceles triangle are, it is important to first understand several things about an isosceles triangle. 1. A triangle has 180 degrees. 2. An isosceles has two equal sides, which means that it also has two equivalent angles. 3. In knowing at least any one angle of an isosceles triangle, it is possible to figure out the other two. Since the base angles are unknown in this question, and they are equivalent to one another, it is a simple algebraic problem. 180 - 70 = 2A 180 is the number of degrees in a triangle 70 is the number of degrees taken up by angle C, with angles A and B being the equivalent base angles. 2a is the double of one base angle. Let's solve. 180 - 70 = 2A 110 = 2A 110/2 = A 55 = A The measure of each base angle is 55.


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