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There is no figure to be seen but an isosceles trapezoid will have equal base angles.

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Dixie Langosh

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Q: If this figure is an isosceles trapezoid what is the measure of dab?
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If this figure is an isosceles trapezoid what is the measure of angle DAB?

There is no figure to be seen but an isosceles trapezoid will have equal base angles.


If the measure of angle DAB is 50 degrees and the measure of angle DAC is 20 degree what is measure of CAB?

If that is the angles of a triangle then the 3rd angle is 110 degrees


Segment AB is the diameter of Circle O Find the measure of angle DAB?

Well, it seems like we need more info about where is point D. And also would be good to know about the angle DOB (this would be an angle that goes from A- to the center"O" and then to B. There should be an DOB. In this case, DOB would be two times the measure of DAB. Let's say that DOB is 90; so DAB is 45.


Why Do the angles of all triangles equal a 180 degrees?

Here is the proof, it is done by drawing parallel lines and using the theorem that alternate interior angles of parallel lines are congruent, which is also easily proved: The Pythagorean proof is even simpler. A line parallel to the base BC is drawn through the vertex A, which gets us two pairs of alternate angles: CBA, DAB and BCA, EAC. Now, angle BAC complements, on the one hand, CBA + BCA to the sum of the angles of DABC, and, on the other, DAB + EAC to two right angles. Basically this says that because a straight line has 180 degrees on each side, and that angles B and C are both alternate interior angles to angles BAD and CAE respectively, angles B and C can both be substituted by angles BAD and CAE. Therefore, you get angle C + angle B + angle A = 180.


How do you construct an angle of 105 degrees using compass?

Using only a compass you cannot do it - you will need a straight edge as well.Draw a straight line AB.From A, using the length AB draw an arc above AB.From B, using the length AB draw an arc to intersect the first arc at C.Join CA.Then angle CAB is 60%From A, draw an arc to cut the two arm of the angle, AB and AC at X and Y respectively.From X, draw an arc between the two arms of angle CAB.Using the same length, repeat from Y so as to cut the previous arc at D.Join DA.DA bisects angle CAB and so angle DAB = 30 degrees.Now bisect angle DAB to give angle EAB = 15 degrees.At A, draw a perpendicular (facing downwards). If F is any point on the perpendicular, the angle EAF = 15 + 90 = 105 degrees.