It's actually 2(pi), you technically need to say 360 degrees. I believe we defined it to be that, but you can prove that it's 360 degrees: Draw a diameter. Draw a second diameter perpendicular to the first. You now have four right angles. Right angles measure 90 degrees. 90 * 4 = 360 Hence, there are 360 degrees in the circle.
Chuck Norris can prove it
There are many things man can not prove. This is one of them.
The circumference of a circle is its boundary - it is a perimeter and therefore is a linear measure. Whether it is a smooth curve, as in the case of a circle, or a set of line segments meeting at vertices is irrelevant to its being linear.
Suppose AB is a chord of a circle which does not pass through its centre.From A, draw the diameter AC. Join BC.Now, by the Circle Theorems (different courses number them differently), angle ABC is a right angle (angle subtended by a semicircular arc).In other words, ABC is a right angled triangle with its right angle at B.If |AB| represents the length of the line AB, and so on,by Pythagoras's theorem, |AC|^2 = |AB|^2 + |BC|^2then since |BC|^2 > 0, |AC|^2 > |AB|^2
Because the circumference of a circle = pi*diameter and pi*1 = pi
The diameter of a circle is its line of symmetry and the lines can be infinite
The area is four times as large if the diameter doubles.The area of a circle is A = (pi)r2 or (pi)(diameter/2)2Since d is squared, it increases the area by the square of 2 if the diameter is doubled.Try calculating the area for a diameter of 2m, 4m and 8m to prove this.
The diameter is a straight angle (180 degrees). The diameter goes through the center of the circle Angles which go through the center of the circle divide the circle into sectors whose area obeys the formula Area = Angle/360 * PI (i'm using a unit circle) that's the approach i'm thinking... not totally sure if that's valid though.
Measure it or bisect it with a compass
There are 5 ways to prove a Quadrilateral is a Parallelogram. -Prove both pairs of opposite sides congruent -Prove both pairs of opposite sides parallel -Prove one pair of opposite sides both congruent and parallel -Prove both pairs of opposite angles are congruent -Prove that the diagonals bisect each other
It's actually 2(pi), you technically need to say 360 degrees. I believe we defined it to be that, but you can prove that it's 360 degrees: Draw a diameter. Draw a second diameter perpendicular to the first. You now have four right angles. Right angles measure 90 degrees. 90 * 4 = 360 Hence, there are 360 degrees in the circle.
Chuck Norris can prove it
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
There are many things man can not prove. This is one of them.
He wanted to prove that you can travel to Antarctica, without freezing.
In any and all circles, the ratio of the circumference to the diameter is a constant called 'pi' ~ 3.14159 and since a full circle contains 2 pi radians = a constant 360 degrees, then the radian itself is a constant angle ~ 180/3.14159 = 57.3'.