All of the angles in an Iscosgon must add up too 3240
There is no such polygon but if you meant exterior angles of 20 degrees then it will have 360/20 = 18 sides
Its exterior angle is 20 degrees and it will have 360/20 = 18 sides
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
Each exterior angle measures 20 degrees Each interior angle measures 160 degrees
If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 20 sides.
It will have 20 sides
Each interior angle will measure 162 degrees
There is no such polygon but if you meant exterior angles of 20 degrees then it will have 360/20 = 18 sides
Interior angle 162 Exterior angle 18 It will have 20 sides
Each interior angle: 1640 20' 52.17''
Its exterior angle is 20 degrees and it will have 360/20 = 18 sides
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
To find the number of sides of a polygon given an interior angle, you can use the formula for the interior angle of a regular polygon: ( \text{Interior Angle} = \frac{(n-2) \times 180}{n} ), where ( n ) is the number of sides. Setting this equal to 3240 and solving for ( n ), we get: [ 3240 = \frac{(n-2) \times 180}{n} ] Multiplying both sides by ( n ) and rearranging gives ( n = 20 ). Therefore, the polygon has 20 sides.
Each exterior angle measures 20 degrees Each interior angle measures 160 degrees
A regular polygon cannot have an interior angle that is less than 60 degrees.
A regular polygon cannot have an interior angle of less than 60 degrees. If it is not regular, then you haven't a hope of answering this question.
If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 20 sides.