To find the number of sides of a polygon given an interior angle, you can use the formula for the interior angle of a regular polygon: ( \text{Interior Angle} = \frac{(n-2) \times 180}{n} ), where ( n ) is the number of sides. Setting this equal to 3240 and solving for ( n ), we get:
[ 3240 = \frac{(n-2) \times 180}{n} ]
Multiplying both sides by ( n ) and rearranging gives ( n = 20 ). Therefore, the polygon has 20 sides.
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
The internal angle sum of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 20 sides, the calculation would be ( (20 - 2) \times 180^\circ = 18 \times 180^\circ = 3240^\circ ). Therefore, the internal angle sum of a polygon with 20 sides is 3240 degrees.
If the 20-sided polygon is a regular polygon, then:The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰Each angle measure = 3240⁰/20 = 162⁰
All of the angles in an Iscosgon must add up too 3240
3240
3240
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
20 sides
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
20
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
20
The internal angle sum of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a polygon with 20 sides, the calculation would be ( (20 - 2) \times 180^\circ = 18 \times 180^\circ = 3240^\circ ). Therefore, the internal angle sum of a polygon with 20 sides is 3240 degrees.