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How many sides does a regular polygon have if the sum of its interior angle measures is 3240?
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
What is the sum of each interior angle in a regular 20 sides polygon?
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
What is the polygon that the sum of the measures of the interior angles is 3240 degrees?
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
What are the interior angles of a 20 sided polygon?
If the 20-sided polygon is a regular polygon, then:The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰Each angle measure = 3240⁰/20 = 162⁰
What are the sizes of each interior angle of a regular polygon that has 170 diagonals showing work?
1 Let the sides be n and use the formula: 0.5*(n2-3n) = diagonals 2 So: 0.5*(n2-3n) = 170 => which transposes to: n2-3n-340 = 0 3 Solving the above quadratic equation gives n a positive value of 20 4 So the polygon has 20 sides and (20-2)*180 = 3240 interior angles 5 Each interior angle measures: 3240/20 = 162 degrees
Interior angle of a polygon with 20 sides?
All of the angles in an Iscosgon must add up too 3240
What is the sum of the interior angle measures of a 20-sided polygon?
3240
What is sum of the interior angle measures of a 20 sided polygon?
3240
How many sides does a regular polygon have if the sum of its interior angle measures is 3240?
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
How many sides does a polygon have if the sum of its interior angles is 3240 degrees?
20 sides
What is the sum of each interior angle in a regular 20 sides polygon?
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
How many sides does a polygon have when the sum of the measures of its interior angles is 3240?
20
What is the size of each interior angle of a regular 20 sides polygon?
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.
What is the polygon that the sum of the measures of the interior angles is 3240 degrees?
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
If the sum of the interior angles of a regular polygon is 3240 degrees how many sides does this polygon have?
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
If the interior angle of a ploygon adds up to 3240 how many sides has it got?
20
What would the total sum of the interior angles be for a polygon with 20 sides?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 3240 degrees
