The ratio of the length of the side of a right angle triangle must be 3,4,5 16,56,65 are not in that ratio.
true
If that '56' has units of 'degrees', then the vertex angle is 68 degrees.
Acute triangle - all of the angles are less than a right angle (90°).Scalene triangle - none of the sides or angles are congruent. It can be shown that if no two angles are the same, then no two sides are the same using the Law of Sines and Law of Cosines.
62 degrees
The ratio of the length of the side of a right angle triangle must be 3,4,5 16,56,65 are not in that ratio.
true
56-ft
If you mean lengths of 33 by 56 by 65 then the given dimensions will form a right angle triangle.
The triangle can be (56, 56, 68) or (56, 62, 62).
56 cm2 * * * * * Only if these are the shorter legs of a right angled triangle and there is no justification for making that assumption. Two sides of a triangle are not sufficient to determine its area.
56 square units
Assuming a right-angle triangle whose length is vertical, and the width is the base, then (14×8) ÷ 2 = 56 square units.
56.08921465 or about 56 square units Worked out by using Pythagoras' theorem and area = 1/2*base*height.
56 sq. units A = 1/2 Base x Height A = 1/2 (7 x 16)
Use Pythagorean Theorem a2+b2=c2 or squareroot(a2+b2)=c Rules for this is that "a" and "b" must be smaller then "c". If you draw a right triangle and draw it as three squares making the right triangle then you will see that the ratio in the formula is proven. so plug the numbers in the formula (usually smallest is "a") so a=14, b=42, c=56 a2+b2=c2 => 142+422=562 => 196+1764=3136 => 1960=3136 As you see 1960 does not equal 3136. Therefore 14,42, and 56 do not make a right angle triangle.
Yes, the three given lengths will form a triangle. Three lengths can make a triangle if, and only if, the sum of the two shorter lengths is greater than the longest length. The two shorter lengths are 56 ft and 16 ft with a sum of 56 ft + 16 ft = 72 ft 72 ft is greater than 65 ft so 56 ft, 65 ft and 16 ft will make a triangle.