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Is the sum of 2 numbers can be odd then there product is odd as well?
Wiki User
∙ 15y ago
Let's take a look at this.
For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd.
Let add them first,
2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even.
Let's multiplied them,
2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too.
So the answer is that when the sum of two numbers can be odd, their product is an even number.
(note that the sum of two odd numbers is even)
Wiki User
∙ 15y ago
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