0.5*(25-15) = 5 diagonals
5
There are five diagonals in a pentagon.
5 diagonals
Yes. A polygon has n(n-3)/2 diagonals, so if n=5: 5(2)/2 =5
1 triangle is formed.
5
It has 5 diagonals.Formula: number of distinct diagonals = n(n-3)/2where n is the number of sides (or vertices)number of diagonals in pentagon:= 5(5-3)/2= 5(2)/2= 10/2= 5Answer: There are 5 diagonals in pentagon.
14
A pentagon has 5 diagonals.
There are five diagonals in a pentagon.
A pentagon has 5 diagonals
no, there are only 5 diagonals in a pentagon.
There are 5 diagonals in a pentagon
a pentagon has 5 diagonals i ur gud at maths...
A five sided pentagon has 5 diagonals
In a pentagon, there are a total of 5 vertices, and lines can be drawn between any two vertices. The number of intersecting lines formed within the pentagon can be determined by considering the diagonals. A pentagon has 5 diagonals, and if we consider all possible pairs of these diagonals, there can be a maximum of 5 intersecting lines inside the pentagon, depending on the arrangement of the diagonals. However, in a simple convex pentagon, only one pair of diagonals will intersect at one point inside.
No. A small pentagon will have smaller diagonals than a large pentagon! However, all the diagonals of a regular pentagon will be congruent.