How many diagonals in irregular pentagon?

Answer 1

An irregular pentagon has five sides. The formula to calculate the number of diagonals in a polygon is given by ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a pentagon (( n = 5 )), the number of diagonals is ( \frac{5(5-3)}{2} = \frac{5 \times 2}{2} = 5 ). Therefore, an irregular pentagon has 5 diagonals.