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4 x 4 and 6 x 3
area 63 and perimeter is 32
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
You can't tell the linear dimensions from knowing only the area. There are an infinite number of shapes that all have the same area. Even if you consider only rectangles, there are still an infinite number of different rectangles, all with different lengths and widths, that all have areas of 5,000 acres.
2l+2w
It is a 3 x 15 rectangle !
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.
You can't tell the dimensions from the perimeter. There are an infinite number of rectangles, with different dimensions, that all have the same perimeter. If it's 168, then the only thing you can be sure of is that the length and width add up to 84, but you can't tell what either of those dimensions must be.
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
4 x 4 and 6 x 3
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.
There is an infinite number that can have that perimeter
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
they dont
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
The perimeter of a rectangle is the sum of its four sides. Add the sides for both rectangles, then compare the results.