Depends what you are drawing on.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
12
36 cm A+
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
Depends what you are drawing on.
There would be an infinite number of rectangles possible
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. So, there are 5 rectangles with an area of 36 cm^2 is 5.
There is no systematic relationship between the two. Consider the following 2 rectangles: A = 8 cm * 8 cm: Perimeter = 32 cm, area = 64 cm2 B = 14 cm * 4 cm: Perimeter = 36 cm, area = 56 cm2 The perimeter of B is larger, but the area is smaller.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
12
2*(5 + 20) cm = 2*25 cm = 50 cm.
330سم
Assuming that it is a square of 9 cm by 9 cm, the perimeter is 36 cm.
36 cm A+
A square with a perimeter of 24 cm has an area of: 36 cm2