They are (a, b-4).
The point which is one unit to the left and 4 units up from the origin.
The point (x, y) is moved to (x+pi/4, y).
Assuming standard notation of (x,y), (5,2) translated 4 down (ie x-4) and 1 left (ie y-1) 5-4=1 2-1=1 (1,1) is the new coordinate
There is not enough information to provide an answer. You need to know the coordinates of three vertices before you can find the coordinates of the fourth. Otherwise, there are alternative solutions using translations, reflections and rotations.
YES From your start point draw a line 5 units up, from this point draw a line 5 units across, from this point draw a line 5 units down, from this point draw a line 5 units back to the start. You have drawn a square with a total perimeter length of 20 units and a area of 25 square units.
The new coordinates are(3 + the old 'x', 2 + the old 'y')
Here's an example: In the coordinate plane, the point is translated to the point . Under the same translation, the points and are translated to and , respectively. What are the coordinates of and ? Any translation sends a point to a point . For the point in the problem, we have the following. So we have . Solving for and , we get and . So the translation is unit to the right and units up. See Figure 1. We can now find and . They come from the same translation: unit to the right and units up. The three points and their translations are shown in Figure 2.
The coordinates are (10, 5).
The coordinates of a point two units to the right of the y-axis and three units above the x-axis would be (2,3).
(-4,-2)
The point which is one unit to the left and 4 units up from the origin.
The new coordinates are (3, -5).
-4
(3,0)
Given only the coordinates of that point, one can infer that the point is located 10 units to the right of the y-axis and 40 units above the x-axis, on the familiar 2-dimensional Cartesian space.
(2,1)
In cartesian coordinates (x, y) = (3, -4)