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Find the measures of an interior angle and an exterior angle of a regular polygon with 9 sides?
Each interior angle: 140 degrees Each exterior angle: 40 degrees
If the measure of one interior angle of a regular polygon is 140 degrees how many sides does the polygon have?
Since interior angle+exterior angle=180 degrees We can find out the exterior angle by doing 180-140=40 degrees. To find out the number of sides we simply do 360/40=9 So the polygon has 9 sides.
If each exterior angle of a regular polygon measures 40 degrees what is the total number of sides in the polygon?
If each exterior angle of a regular polygon measures 40 degrees, the polygon is a nonagon (9-sided polygon).
What is the measure of an exterior angle of a 40-gon?
Finding the exterior angle of a regular polygon is really simple, divide 360 by the number of sides. So: 360/40=9 degrees.
What is the interior and exterior angle of a regular 9 sided polygon?
The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nSubstituting with n=9, then the answer is that the interior angle = 140The measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nSubstituting with n= 9, then the answer is that the exterior angle = 40
