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If its a regular 9 sided polygon then the exterior angles are 40 degrees.

Q: What is the exterior angle of a 9 sided polygon?

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1620

140

Since the interior angle measure of the regular polygon is 140⁰, its exterior angle measure is 180⁰ - 140⁰ = 40⁰. Since the sum of the exterior angle measures is 360⁰, the polygon has 360⁰/40⁰ = 9 sides.

Interior angle = 140 deg so exterior angle = 40 deg. Sum of exterior angles = 360 so 360/40 = 9 such angles required. So the figure has 9 sides.

If each interior angle is 171 degrees then each exterior angle is 180-171 = 9 degrees. Sum of all exterior angles (irrespective of number of sides) is 360 degrees So number of sides = 360/9 = 40

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If each exterior angle is 9 degrees then it is a regular 40 sided polygon.

40

360 / 9 = 40

40

The measure of an interior angle in degrees of a regular polygon of n sides is given by the formula: 180 x (n-2) / nSubstituting with n=9, then the answer is that the interior angle = 140The measure of an exterior angle in degrees of a regular polygon of n sides is given by the formula: 360/nSubstituting with n= 9, then the answer is that the exterior angle = 40

If each exterior angle of a regular polygon measures 40 degrees, the polygon is a nonagon (9-sided polygon).

400 exterior angle = 360/9 = 400

A regular polygon with an exterior angle of40O is a nonagon, and has 9 sides.

1620

140

The exterior angle would have to be greater than 180 degrees. If you mean interior angle then a regular nonagon (9 sided) will have angles of 140 degrees.

Each central angle of a regular 9 sided polygon: 360/9 = 40 degrees