Prove that the maximum vertex connectivity one can achieve with a graph G on n.
01.
Define a bipartite graph. Prove that a graph is bipartite if and only if it contains no
circuit of odd lengths.
Define a cut-vertex. Prove that every connected graph with three or more vertices
has at least two vertices that are not cut vertices.
Prove that a connected planar graph with n vertices and e edges has e - n + 2 regions.
02.
03.
04.
Define Euler graph. Prove that a connected graph G is an Euler graph if and only if
all vertices of G are of even degree.
Prove that every tree with two or more vertices is 2-chromatic.
05.
06.
07.
Draw the two Kuratowski's graphs and state the properties common to these graphs.
Define a Tree and prove that there is a unique path between every pair of vertices in a
tree.
If B is a circuit matrix of a connected graph G with e edge arid n vertices, prove
that rank of B=e-n+1.
08.
09.
A hexagon has more vertices.
Hexagons have more than 5 verticies. Not pentagons because they have exactly 5 verticies. not a quadrilateral because that has 4 vertices. not a triangle because it has 3 vertices but left down to Hexagon which has 6 vertices .
Triangular prism has 6 vertices. Triangular pyramid has 4 vertices. 6-4 = 2 Answer: 2 vertices.
it has 4 vertices, a vertice is a point were two lines intersect
no
Every polygon that is not a triabgle (3 vertices), quadrilateral (4 vertices) or pentagon (5 vertices) has more than 5 vertices.
A hexagon has more vertices.
the vertex is where the two or more edges meet so to find them just count the corners because every corner is a vertex. a cube has 8 Vertices
Both vertices and vertexes are acceptable, but vertices is more commonly used.
The number of vertices does not determine the number of faces. If the shape with 6 vertices was a quadrilateral based bipyramid, it would have 8 faces. A hexagonal based pyramid has 7 vertices and 7 faces. So more vertices does not necessarily imply more faces.
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A rectangular prism has 8 vertices, a rectangular pyramid has 5 vertices, 8-5=3 more vertices, so yes.
11 vertices (one more than the number of vertices in the base).
2 more vertices
3 more vertices
A cube has 8 vertices and 6 faces. Therefore a cube has 2 more vertices than faces.
2 more vertices