The theorem is only true if the base is the side of different length.
To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.
So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.
Consider triangles AXB and AXC.
Thus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.
Thus XB must be the same length as XC, that is X is the mid-point of BC.
As X is the mid-point of BC, AX is the median.
Altitude APEXX
It is isosceles.
It is isosceles.
Isosceles.
B. The same segment. ~Ãpex
Yes
If the triangle is really isosceles, and it's not lying on one of the equal sides, then the altitude is always a median.
Altitude APEXX
It is isosceles.
It is isosceles.
in an isosceles triangle
Isosceles.
An isosceles or an equilateral triangle perhaps?
You can find it by using the Pythagorean theorem if you know the side and the base of triangle. In an isosceles triangle the median is also the altitude. The formula is: (The measure of the side length)^2 - (The measure of the one half of the base length )^2 = (The measure of the altitude)^2. Find the square root of the result that you'll have the measure of the altitude.
B. The same segment. ~Ãpex
Yes, if the triangle is isosceles or equilateral.
It is the median which divides the side which is not one of the equal sides.