p^2+q^2=2(a^2+b^2)
where
p,q=diagonals of the parallelogram
a,b=sides of the parallelogram
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False. Bisecting diagonals is sufficient to guarantee a parallelogram, but the diagonals will only be perpendicular if the sides of the parallelogram are equal.
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
the diagonal in a paralleogram is not equal but the diagonals in the rectangle are congruent this is because the opposite sides of a parallelogram and rectangle are same parallel to each other but the adjacent sides of a parallelogram is not perpendicular where as the adjacent sides of rectangle is perpendicular to each other.
N(N-3)/2where N is the number of sides of a Polygon.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.