answersLogoWhite

0

p^2+q^2=2(a^2+b^2)

where

p,q=diagonals of the parallelogram

a,b=sides of the parallelogram

User Avatar

Wiki User

12y ago

Still curious? Ask our experts.

Chat with our AI personalities

LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
ProfessorProfessor
I will give you the most educated answer.
Chat with Professor

Add your answer:

Earn +20 pts
Q: Relationship between diagonals and sides of a parallelogram?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Geometry

True or false the diagonals of a quadrilateral must bisect each other and be perpendicular to guarantee that the quadrilateral is a parallelogram?

False. Bisecting diagonals is sufficient to guarantee a parallelogram, but the diagonals will only be perpendicular if the sides of the parallelogram are equal.


What is the relationship between the number of sides of a polygon and the number of diagonals?

Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.


Are diagonals of equal length in a parallelogram and rectangle?

the diagonal in a paralleogram is not equal but the diagonals in the rectangle are congruent this is because the opposite sides of a parallelogram and rectangle are same parallel to each other but the adjacent sides of a parallelogram is not perpendicular where as the adjacent sides of rectangle is perpendicular to each other.


What is the relationship between diagonals to the number of sides?

N(N-3)/2where N is the number of sides of a Polygon.


Prove that if the diagonal of a parallelogram does not bisect the angles through the vertices to which the diagonal is drawn the parallelogram is not a rhombus?

Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.