Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
p^2+q^2=2(a^2+b^2) where p,q=diagonals of the parallelogram a,b=sides of the parallelogram
38 diagonals
The sides are equal The angle between adjacent sides is 90 degrees There are two diagonals The diagonals are equal in length The diagonals make 90 degrees with each other The diagonals make 45 degrees with the sides
1/2*(n2-3n) = number of diagonals where n is the number of sides of the polygon.
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
p^2+q^2=2(a^2+b^2) where p,q=diagonals of the parallelogram a,b=sides of the parallelogram
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
relationship between the number of sides of afigure and the number of vertices
A 7 sided polygon has 14 diagonals
It has 20 diagonals
If it has 28 sides then it has 350 diagonals by using the formula 0.5(n^2 -3n) whereas 'n' means number of sides
The five sided Polygon has 5 diagonals
38 diagonals
number of diagonals = n(n-3)/2 n - number of sides of the polygon
Number of sides - 2
The number of diagonals in an equilateral figure can be calculated from the number of sides. If the number of sides is "S", then the number of diagonals would be S(S-3)/2 This becomes clear if you consider that there will be the same number of vertices as there are sides. From each vertex you can draw a diagonal to all vertices except the one you started from and the two adjacent ones (lines between the adjacent vertices and the starting point are sides of the figure, not diagonals). This gives you S·(S-3) but that would double count the diagonals since each diagonal can start at either vertex.