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The sum of the exterior angles of any polygon is 360 degrees. this is true whether the figure is regular or irregular, and irrespective of how many sides/vertices it has. For a regular nonagon, the 9 equal external angles sum to 360 degrees and so each measures 360/9 = 40 degrees.

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Each exterior angle is 360/9 = 40 degrees

Q: Size of an exterior angle of a regular nonagon?

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360/9 = 40 degrees

135 degrees and its exterior angle is 45 degrees

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°

interior = 720/6 = 120 so exterior = 180 - 120 = 60 degrees

Exterior angle = 360/16 = 22.5 So interior angle = 180 - 22.5 = 157.5 degrees.

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360/9 = 40 degrees

360/9 ie 40 degrees

Each interior angle measures 140 degrees

Each exterior angle is 360/6 = 60 degrees

135 degrees and its exterior angle is 45 degrees

Exterior angles are supplementary with interior angles, so 180-30=150

Exterior angle = 14.4 degrees Interior angle = 165.6 degrees

exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°

It can be any size at all, between zero and 360 degrees.If the nonagon is regular, then the angle measures 140 degrees.

Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees

162 degrees

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°