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The sum of the exterior angles of any polygon is 360 degrees. this is true whether the figure is regular or irregular, and irrespective of how many sides/vertices it has. For a regular nonagon, the 9 equal external angles sum to 360 degrees and so each measures 360/9 = 40 degrees.

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8y ago

Each exterior angle is 360/9 = 40 degrees

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Q: Size of an exterior angle of a regular nonagon?
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Related questions

What is the size of each exterior angle of a regular nonagon a 9 sided shape?

360/9 = 40 degrees


What is the size of an exterior angle of nonagon?

360/9 ie 40 degrees


What is the size of an interior angle in a regular nonagon?

Each interior angle measures 140 degrees


What is the size of one exterior angle in a regular hexagon?

Each exterior angle is 360/6 = 60 degrees


What is the size of one interior angle in a regular octagon?

135 degrees and its exterior angle is 45 degrees


A regular polygon an exterior angle of 30 What is the size of the interior angle?

Exterior angles are supplementary with interior angles, so 180-30=150


What is the size of each angle in a regular 25 sided shape?

Exterior angle = 14.4 degrees Interior angle = 165.6 degrees


What is the size of an interior angle of a 20 sided regular polygon?

exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°


What is the messurement of 1 interior angle in a nonogone?

It can be any size at all, between zero and 360 degrees.If the nonagon is regular, then the angle measures 140 degrees.


What are the size of exterior angles of hexagon?

Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees


D Find the size of each exterior angle of a regular 20-gon?

162 degrees


What is the size of each interior angle of a regular polygon with 28 sides?

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°