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Q: Size of interior angle of regular pentagon?

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To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o

Each interior angle is: 1520 18' 27.69''

Each interior angle of the regular 8 sided octagon measures 135 degrees

135 degrees and its exterior angle is 45 degrees

Providing that it is a regular 15 sided polygon then each interior angle will be 156 degrees

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thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees

To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o

The answer depends on the curvature relative to the size of the pentagon.

Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.

108 degrees The sum of all interior angles of a polygon is equal to the following: 180n-360, where n is the number of sides. For n=5, the total of all of the angles is 180*5-360=900-360=540. Since every angle in a regular polygon, each interior angle of a regular pentagon is 540/5=108 degrees.

Each interior angle is 150 degrees

Each interior angle is 144 degrees

Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!

Each interior angle measures 140 degrees

120 degrees.

Each interior angle is 162 degrees.

Each interior angle: 1640 20' 52.17''

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