false
The Koch curve was first described in 1904.
A line segment
R = radius c = chord length s = curve length c = 2Rsin(s/2R) you can solve for radius by trial and error as this is a transcendental equation
A curve is formed by lines. If the length of these lines is reduced to zero, we get a very smooth curve.
tan A = (sin A) / (cos A) tan (A)= opposite side length/adjacent side length A is an angle measurement; amount of degrees or radians. If a line is tangent to a curve, it only touches the curve at one point. looks like )| but the line is touching the curve. In a circle, the tangent line touches the circle at one point and is perpinducular to the circle's radius if it is touching that same point.
A Koch curve has INFINITE length.
infinate
The Koch curve is considered infinite because it is created through an iterative process that adds infinitely many segments to its structure. Starting with a straight line, each iteration replaces the middle third of each line segment with two segments that form a triangle, increasing the total length without bound. As this process continues indefinitely, the curve's length approaches infinity, while the overall shape remains a finite area. Thus, the Koch curve exemplifies a fractal, showcasing complexity and infinity within a finite space.
true
The Koch curve was first described in 1904.
A variety of such shapes can be constructed; a well-known example is the Koch snowflake. http://en.wikipedia.org/wiki/Koch_snowflake
koch curve
Koch Curve APEX :)
4
yes! the best example would be the Koch snowflake.
A line segment.
It is self-similarIt has infinite length.It has fractional dimension.Apex - TFthis is the correct apexvsCheck all that apply.xA.It is self-similar. B.It has finite length.xC.It is constructed by repeatedly bending a line segment.xD.It has fractional dimension. E.It requires a total of four iterations to construct.