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Let the base be x+3 and the height be x:

Area = 1/2*(x+3)*x = 44 cm2

x2+3x = 88

x2+3x-88 = 0

Solving the above quadratic equation will work out as:

x = -11 or x = 8, so x must be the latter because dimensions can't be negative.

Therefore: base = 11 cm and height = 8 cm

Check: 1/2*11*8 = 44 cm2

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Q: The base of a triangle is 3 cm greater than the height the area is 44 cm2 find the height and lengt of the base?
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