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Area of bullseye 102 ie 100pi;

Area of inner ring and bullseye together is 252 ie 625pi, so area of inner ring is 525pi.

Area of second ring and its contents is 402 ie 1600pi, contents area 625pi so area of second ring 975pi.

Area of third ring and contents is 552 ie 3025pi, contents area is 1600pi so area of third ring is 1425pi

Area of outer ring and contents is 702 ie 4900pi, contents area is 3025pi so area of outer ring is 1875pi.

I note that for the three outer rings the area increases by 450pi each time, but for the inner ring it only increases by 425pi. What the reason for this is, I know not unless I've miscalculated somewhere...

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Q: The bull's eye of a target is a circle 20cm in diameter. It is surrounded by four rings each 15cm wide Find the area of each ring?
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