The length of arc ACB is 57.2.
All you've told us is that 40 cm is less than 1/2 of the circumference. With that information, all we know is that the circumference is more than 80 cm. We could calculate it if we knew what the angle is at the center of circle between the two radii (radiuses) that go to the ends of arc AB. We're guessing that it's there in your book, but you forgot to include it when you decided to ask us to do your homework problem for you.
Semicircle
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
The picture that you see printed next to that question on the assignment sheet is necessary in order to answer it. Without the picture, I have no idea how angle-1, arc-ab, and arc-ag are connected .
The length of arc ACB is 57.2.
Arc AB represents 40/240 = 1/6 of the circumference of the circle. As the angle at the centre subtended by the whole circle is 360° then ∠A0B (if the center is O) measures 1/6 x 360 = 60°. Since a central angle has the same number of degrees as the arc it intercepts, the arc ACB (note we can call the arc AB as arc ACB) measures 60°.
The equation for finding the length of an arc is S=rθ,where S is the arc length, r is the radius, and θ is the angle in radians.Assuming you mean AOB=240 is the angle of the arc you are measuring in degrees:θ=(pi*240)/180=4.1888radTherefore the arc length is 4cm*4.1888rad=16pi/3=16.76cm
length work
Ab+ac+5mp=acb
All you've told us is that 40 cm is less than 1/2 of the circumference. With that information, all we know is that the circumference is more than 80 cm. We could calculate it if we knew what the angle is at the center of circle between the two radii (radiuses) that go to the ends of arc AB. We're guessing that it's there in your book, but you forgot to include it when you decided to ask us to do your homework problem for you.
circumference of the circle = 2*pi*10 = 20pi units of measurement length of arc = (120/360)*20pi = 20.944 units (rounded to 3 decimal places)
30
Semicircle
If angle ACB is the right angle then ab is the hypotenuse. Then, (ab)2 = 62 + 92 = 36 + 81 = 117 ab = √117 = 10.8 (3 sf) If angle BAC is the right angle then ab is one leg of a right angled triangle with bc the hypotenuse. 92 = 62 + (ab)2 : (ab)2 = 92 - 62 = 81 - 36 = 45 ab = √45 = 6.71 (3 sf)
The picture that you see printed next to that question on the assignment sheet is necessary in order to answer it. Without the picture, I have no idea how angle-1, arc-ab, and arc-ag are connected .
Place the point if the compass on point B and draw an arc across AB.