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Q: The line parallel to line r that contains 1 -1?

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yes it has 1 line of symmetry right through the middle but plain lines r different

line r

In trigonometry, the value of R is the radius of the circle, and is usually normalized to a value of 1. If the circle is at the X-Y origin, and theta is the angle between the radius line R, and X and Y are the X and Y coordinates of the point on the circle at the radius line, then... sine(theta) = Y / R cosine(theta) = X / R secant(theta) = 1 / cosine(theta) = R / X cosecant(theta) = 1 / sine(theta) = R / Y

It is 12.

There are letters in the alphabet with both parallel and perpendicular lines. In alphabetical order, they are E, F, and H. If the joining point can be considered perpendicular and parallel, then B, D, P, and R also match the criterion.

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Lines r and m are parallel or line r is line m continued

1/R= 1/R+1/R+1/R.... The first R is total resistance and the other R's are the resistances of the individual resistors

different times lines r interesting

No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.

Call the total effective resistance 'R'. If the values of the individual parallel resistors are 'A', 'B', 'C', 'D' etc., then 1/R = (1/A) + (1/B) + (1/C) + (1/D) etc. Or, R = 1 divided by { (1/A) + (1/B) + (1/C) + (1/D) } The more resistors there are in parallel, the SMALLER the effective resistance becomes.

The total resistance of a parallel circuit can be found by setting the inverse of the unknown total resistance equal to the sum of the inverse resistances of each resistor. In equation form: 1/R(total) = 1/R(1) + 1/R(2)... (and so on)

Use the formula for parallel resistances: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 ... Where "R" is the final or equivalent resistance; and R1, R2, R3, etc. are the resistances of the individual parallel branches. As a shortcut, for the special case of identical resistance values, the parallel combination of two resistances is one-half the value of each resistance; the parallel combination of three resistances is one-third the value of each resistance, etc. Another shortcut (only works for two resistances at a time) is: R = (R1 x R2) / (R1 + R2)

Inductors in Series - L total = L1 + L2 +L3. Inductors in Parallel - 1/Lt = 1/L1 + 1/L2 + 1/L3 Resistors in Parallel - 1/R total = 1/R1 + 1/R2 + 1/R3 Resistors in Series - R total = R1 + R2 + R3

1/R=1+0.01 so R=1/1.01 so R=0.99 ohm

No. The reciprocal is additive. The formula for the equivalent resistance, in parallel, is 1/R = 1/R1 + 1/R2 + 1/R3... where R is the total equivalent resistance, and R1, etc. are the individual resistances in parallel. Note that the equilalent resistance will be less than any of the individual resistances.

Parallel resistance refers to 2 or more resistors where the input sides are connected together and the output sides are connected together. The formula to calculate it is the inverse of the total resistance of the circuit is equal to the sum of the inverses of the individual resistances. 1/R (total) = 1/R (1) + 1/R (2) + 1/R (3) + …

R=1/(1/ R1 +1/ R2 +1/ R3 +.........) Where R is the total external resistance(effective resistance) in an electric circuit.

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