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How many minimum edges in a Cyclic graph with n vertices?
The term "cyclic graph" is not well-defined. If you mean a graph that is not acyclic, then the answer is 3. That would be the union of a complete graph on 3 vertices and any number of isolated vertices. If you mean a graph that is (isomorphic to) a cycle, then the answer is n. If you are really asking the maximum number of edges, then that would be the triangle numbers such as n (n-1) /2.
What is the minimum number of vertices needed to form a polygon?
Three of them in the form of a triangle.
What do you notice about the number of sides and the number vertices apolygon has?
The number of sides and vertices are the same
What is the relationship between faces vertices and edges in prisms?
In a prism, the number of faces, vertices, and edges are related by the formula F + V - E = 2, known as Euler's formula. For a prism, which has two parallel and congruent faces connected by rectangular faces, the number of faces (F) is equal to the sum of the number of rectangular faces and the two congruent bases. The number of vertices (V) is equal to the number of corners where edges meet, and the number of edges (E) is equal to the sum of the edges around the bases and the edges connecting the corresponding vertices of the bases.
Do prisms and pyramids have the same number of vertices?
No, prisms and pyramids do not have the same number of vertices. A prism has two identical polygonal bases connected by rectangular faces, so it has 2 more vertices than the number of sides in the base polygon. A pyramid has a polygonal base and triangular faces connecting the base to a single vertex, so it has 1 more vertex than the number of sides in the base polygon.
How many minimum edges in a Cyclic graph with n vertices?
The term "cyclic graph" is not well-defined. If you mean a graph that is not acyclic, then the answer is 3. That would be the union of a complete graph on 3 vertices and any number of isolated vertices. If you mean a graph that is (isomorphic to) a cycle, then the answer is n. If you are really asking the maximum number of edges, then that would be the triangle numbers such as n (n-1) /2.
The minimum number of edges in a connected graph on n vertices is?
n-1 (o-o-o-o-o)
What prisms have vertices?
Every prism has vertices. They have an even number of vertices, with a minimum of 6 and no maximum.
What is the minimum number of vertices needed to form a polygon?
Three of them in the form of a triangle.
Does a prism have an even number of vertices?
Yes, a prism has an even number of vertices. A prism is a three-dimensional shape with two parallel and congruent polygonal bases connected by rectangular or parallelogram faces. The number of vertices in a prism is equal to the number of vertices in its bases plus the number of vertices in the lateral faces. Since each base has an equal number of vertices, and the lateral faces have an even number of vertices, the total number of vertices in a prism is always even.
What is the minimum number of vertices of 3-regular graph with girth 6?
-3
What is the minimum number of triangles required to triangulate an hendecagon?
9 (two less than the number of vertices in the polygon).
How many Number of vertices a triangular prism have?
A triangular prism has six vertices. It has three vertices at the top triangular face and three corresponding vertices at the bottom triangular face. The two triangular faces are connected by three rectangular faces.
If faces plus edges equals vertices plus what number follows?
There is no answer to the question as it appears. Faces + Vertices = Edges + 2 (The Euler characteristic of simply connected polyhedra).
What is the formula related vertices and edges?
There is not a specific formula fro vertices and edges. The Euler characteristic links the number of vertices, edges AND faces as follows: E + 2 = V + F for a simply connected polyhedron.
What 3D shape has 6 faces 8 vertices and 8 edges?
There can be no simply connected polyhedron with the specified number of faces, vertices and edges. The Euler characteristic requires that F + V = E + 2 where F = number of faces V = number of vertices E = number of edges This requirement is clearly not satisfied.
Show that a tree has at least 2 vertices of degree 1?
A tree is a connected graph with no cycles. By definition, a tree with ( n ) vertices has ( n - 1 ) edges. If we assume there are no vertices of degree 1, then every vertex must have a degree of at least 2. This would imply that the minimum number of edges required to connect the vertices in such a case would exceed ( n - 1 ), leading to a contradiction. Therefore, a tree must have at least two vertices of degree 1, which are typically the leaf nodes.
