The term "cyclic graph" is not well-defined.
If you mean a graph that is not acyclic, then the answer is 3. That would be the union of a complete graph on 3 vertices and any number of isolated vertices.
If you mean a graph that is (isomorphic to) a cycle, then the answer is n.
If you are really asking the maximum number of edges, then that would be the triangle numbers such as n (n-1) /2.
n-1
V*(V-1)/2
No.No.No.No.
o(n^2)
Oh, dude, let me break it down for you. So, each vertex has degree 2, which means each vertex is connected to two edges. Since there are 7 vertices, you would have 7 * 2 = 14 edges in total. Easy peasy, right?
n-1
n-1 (o-o-o-o-o)
No, the complete graph of 5 vertices is non planar. because we cant make any such complete graph which draw without cross over the edges . if there exist any crossing with respect to edges then the graph is non planar.Note:- a graph which contain minimum one edge from one vertex to another is called as complete graph...
Yes.
If all the vertices and edges of a graph A are in graph B then graph A is a sub graph of B.
A drawing of a graph or network diagram is a pictorial representation of the vertices and edges of a graph. This drawing should not be confused with the graph itself: very different layouts can correspond to the same graph. In the abstract, all that matters is which pairs of vertices are connected by edges.
11......
- Two or more edges that join the same pair of vertices in a graph. Also known as multiple edges.
A cubic graph must have an even number of vertices. Then, a Hamilton cycle (visiting all vertices) must have an even number of vertices and also an even number of edges. Alternatively color this edges red and blue, and the remaining edges green.
36 vertices if all of them are or order two except one at each end.
Some common graph vocabulary words include vertices (or nodes), edges (or links), directed edges (or arcs), weighted edges, and adjacency matrix.
In a graph, the sum of the degrees of all vertices is equal to twice the number of edges. This is known as the Handshaking Lemma. Therefore, if all vertices in a graph with 35 edges have a degree of at least 3, the sum of the degrees of all vertices must be at least 3 times the number of vertices. Since each edge contributes 2 to the sum of degrees, we have 2 * 35 = 3 * V, where V is the number of vertices. Solving for V, we get V = 70/3 = 23.33. Since the number of vertices must be a whole number, the largest possible number of vertices in this graph is 23.