Let the breadth = x
So, length = 2x+1
Thus perimeter will be,
2(2x+1+x)=122
= 6x+2=122
So, 6x=122-2=120
So, x= 120/6=20
Therefore length=2x+1=2(20)+1=41
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
98 square feet
Well, if you're talking about a square, then the perimeter is twice the length plus twice the width; in this case it would be 30 feet...
12 meters
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Given: 2w + 2l = 34 l = w + 2 Then: 2w + 2(w + 2) = 34 4w = 30 w = 7.5 l = 9.5
Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.
Perimeter of a rectanle is the sum of twice the length and twice thewidth. 140 + 140 + 2 x W = 410 2W = 410-280 = 130 W = width = 65 meters
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
To calculate the perimeter of a rectangle one adds twice the width and twice the length... in this case (2 x 3 metres) + (2 x 7 metres) = 6 metres + 14 metres = 20 metres.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Area is length times width, perimeter is twice the sum of length and breadth.