Let the length of other side be L,
Then,
2L+ 2(W/2) = 6W
L= 5W/2
Area = 5W/2 * W/2
=(5W^2)/4
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The perimeter of a rectangle is total length of all 4 sides = 2 x length + 2 x width. The semiperimeter is therefore half this amount = length + width.
Half an acre = 21780 sq feet.This could have a perimeter of any length greater than (or equal to) 523.16 feet.If the area is in the form of a circle of radius 83.26 feet, it will have the minimum perimeter of 523.16 feet.Or, you can have a square of 147.6 ft giving a perimeter of 590.3 ft,or a rectangle of 150 ft * 145.2 ft - perimeter = 590.4 ftor a rectangle of 100 ft * 217.8 ft - perimeter = 635.6 ftor a rectangle of 10 ft * 2178 ft - perimeter = 4376 ftor a rectangle of 1 ft * 21780 ft - perimeter of = 43562 ftetc, with the perimeter increasing without limit.Or, the area could be circular giving the minim590 feet.
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
To find the area of a rectangle, when you only know the perimeter, you can just just break the sides down into two pairs of lengths. For example; if the known perimeter is 100, you can call the two short sides, we'll call those the width, 10 (x2=20) and the two long sides, we'll call those length, 40 (x2=80) 20+80=100... Now you know all the lengths of the sides, so the area formula is L x W = area or 10 x 40 = 400. Any rectangle with a perimeter of 100 will have an area of 400, no matter what the lengths are and the process works for any rectangle, you just have to break the perimeter length down into two pairs of lengths.+++That starts off right but is NOT the full method.'You need to know the ratio between its length and breadth. Then apply that ratio to half of the perimeter to find the length and breadth.'Try it:L = 4, B= 6 so P = 20 but Area = 4 X 6 = 24 square units.L = 2, B = 8 so P = 20 again BUT Area now = 2 X 8 = 16 sq. units.For any given rectangle perimeter, there is an infinite number of possible areas.For a quadrilateral, Perimeter-only works only for the Square, for which A = [P/4]^2 = [(P^2)/16]
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
Length + width = half the perimeter, but more info eg area, is needed.
width=9 length=18
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 unit will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.+++To summarise, you can, IF you know the ratio as mentioned. Then apply that to half the perimeter to find the length and breadth.
edit: just check answer, answer was wrong
The perimeter of that rectangle is 89.6875.
Length + width = half of perimeter, ie 18 cm. 18 - 4 = 14, 14/2 = 7 so sides are 7 and 11 cm and area = 77sq cm
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Length + width = half perimeter = 100". Length is 98", width is 2"
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
Because a triangle is half of a rectangle. The area of a rectangle is length times width, the area of a triangle is half that.
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.