Length + width = half of perimeter, ie 18 cm. 18 - 4 = 14, 14/2 = 7 so sides are 7 and 11 cm and area = 77sq cm
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle is found by the following formula: (Length x 2) + (Width x 2) or Length + Length + Width + Width.
Length + length + width + width = perimeter. Length + width x 2 = perimeter
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
21cm3
the width equals 14 cm. and the length equals 31 cm.
width=9 length=18