Assume the room is rectangular.
If the width is w then the length is w + 1. The perimeter is 2w + 2(w + 1) = 4w + 2.
4w + 2 = 14 : 4w = 12 : w = 3 meters
The perimeter would be 28 meters.
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
The length of the floor is 5.5 meters because 2*(5.5+5) = 21 meters which is the perimeter
width=5 length=12
Area can never be as low as the perimeter value -- impossible question.No impossible if read correctly...18 meters squared is the area and 18 meters is the perimeter.
The perimeter is 82 meters.
Measure it with a meter stick. Multiply the length times the width to find the area. Two times the length plus two times the width is the perimeter.
The perimeter would be 28 meters.
The perimeter is 42 metres.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
12 meters
134 meters
= If a rectangle is 10 meters longer than its width what is its width? =
Width: 16 meters Length: 21 meters Check: 16+21+16+21 = 74 meters which is its perimeter
24 meters
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
Perimeter of a rectangle = twice (length + width), in this case 22 m.