= If a rectangle is 10 meters longer than its width what is its width? =
width is 5 feet
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
Suppose the width=x so the length will be= (2x+3) Now perimeter of rectangle = 2(length+width) so, 186=2(x+2x+3) or, 3x+3=93 or, 3x=90 so, x=30 so the width of the rectangle is 30meters
Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!
12 meters
L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.
width is 5 feet
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
21cm3
The width is 6 feet. The length is 8 feet.
The length is 7 feet and the width is 5 feet
width=5 length=12
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
Suppose the width=x so the length will be= (2x+3) Now perimeter of rectangle = 2(length+width) so, 186=2(x+2x+3) or, 3x+3=93 or, 3x=90 so, x=30 so the width of the rectangle is 30meters
Prime factors of 55 are 5 and 11, which differ by 6, so length 11m, width 5m!