Using Pythagoras' theorem the diagonal works out as 51 inches
Diagonal of a square of side s is given by: d = 21/2s We have, d = 13 inches So, using the above formula we get, s = d/21/2 = 13/21/2 inches = 9.193 inches
The height of an object given a length of 50 inches.
The rectangle has a length of 12.
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
Diagonal of a square of side s is given by: d = 21/2s We have, d = 13 inches So, using the above formula we get, s = d/21/2 = 13/21/2 inches = 9.193 inches
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
Given a diagonal of 7.125 inches, the square has the following measurements:Side lengths of 5.038 inchesPerimeter of 20.15 inchesVolume of 25.38 inches2
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
Television set sizes are typically given diagonally. That is the diagonal size of the screen, not the entire cabinet. Some manufacturers are now using weasel-words like "40 inch class" when their TV is actually less than 40 inches.
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
Television screen 'sizes' are given as the length of the actual diagonal measurement of the screen e.g. bottom left corner to top right corner of the screen.The actual height and width of the screen is determined by its 'aspect ratio', i.e. the ratio between its width and its height. (Some televisions are 'widescreen'!)If a 26" screen has an aspect ratio of 16:9, it will be* 22.66 inches wide, and * 12.75 incheshigh. Of course, the overall dimensions of the television will be bigger than the screen size, depending on the particular brand and style.
The answer depends on whether the base is one of the legs of the right angle or the hypotenuse. Also, a triangle cannot have a diagonal.
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square