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What is the height of a trapezoid with an area of 62.5 and the two bases as 11 and 14?
Height: (62.5*2)/25 = 5
A trapezoid has bases of 7 centimeters and 5 centimeters and a height of 3 centimeters What is its area?
The formula for area a is height X average of the two parallel bases of the trapezoid. In this instance, a = 3[(7 + 5)/2] = 18 square centimeters.
What is the area of a trapezoid if its bases are 12 and 18 meters long and its height is 4 meters?
the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2
Find the area of isosceles trapezoid with height of 5 nonparallel sides of 6 and bases of 8 and 10?
((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45
What is the approximate area of a trapezoid with these dimensions 6 times 12 times 5 times 10 and a height that is 4?
Area of a trapezoid measured in square units = 0.5*(sum of parallel sides)*height
A trapezoid has an area of 28ft2 The two bases are 5 ft and 9 ft What is the height of the trapezoid?
4 ft.
What is the area of a trapezoid if the meausure of the base is 8 and the height is 5?
Area of a trapezoid = 0.5*(sum of parallel bases)*height Need to know the measure of the other base
What is the height of a trapezoid with an area of 62.5 and the two bases as 11 and 14?
Height: (62.5*2)/25 = 5
A trapezoid has bases of 7 centimeters and 5 centimeters and a height of 3 centimeters What is its area?
The formula for area a is height X average of the two parallel bases of the trapezoid. In this instance, a = 3[(7 + 5)/2] = 18 square centimeters.
What is the area of a trapezoid if its bases are 12 and 18 meters long and its height is 4 meters?
the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2
What is the height of a trapezoid that has an area of 65 and bases that equal 13?
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
What is the area of a trapezoid bases are 12Cm and 8Cm and the height is 5Cm?
1/2*(12+8)*5 = 50 square cm
What is the area of a trapezoid with bases 5 km 7 km and height 3 km?
It is 0.5(5 + 7)*3 = 6*3 = 18 km2
Find the area of a trapezoid with the bases of 6centimeters and 8centimeters with the height of 5centimeters?
Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2
A trapezoid has bases of 7 cm and 5 cm and a height of 3 cm. what is its area?
The area of a trapezoid can be calculated using the formula: ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ), where ( b_1 ) and ( b_2 ) are the lengths of the bases, and ( h ) is the height. For this trapezoid, the area is ( \frac{1}{2} \times (7 , \text{cm} + 5 , \text{cm}) \times 3 , \text{cm} = \frac{1}{2} \times 12 , \text{cm} \times 3 , \text{cm} = 18 , \text{cm}^2 ). Thus, the area of the trapezoid is 18 cm².
Mateo graphs trapezoid JKLM which has a height of 3 units and bases of 5 units and 7 units. Mateo then reflects JKLM across the y-axis to create J'K'L'M'. What is the area of J'K'L'M' in square units?
Area of trapezoid: 0.5*(5+7)*3 = 18 square units
Find the area of isosceles trapezoid with height of 5 nonparallel sides of 6 and bases of 8 and 10?
((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45
