Q: Trapezoid has bases of 9 in and 7 in and height of 5 what is the area?

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Height: (62.5*2)/25 = 5

The formula for area a is height X average of the two parallel bases of the trapezoid. In this instance, a = 3[(7 + 5)/2] = 18 square centimeters.

the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2

((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45

Area of a trapezoid measured in square units = 0.5*(sum of parallel sides)*height

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4 ft.

Area of a trapezoid = 0.5*(sum of parallel bases)*height Need to know the measure of the other base

Height: (62.5*2)/25 = 5

The formula for area a is height X average of the two parallel bases of the trapezoid. In this instance, a = 3[(7 + 5)/2] = 18 square centimeters.

the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2

The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.

1/2*(12+8)*5 = 50 square cm

It is 0.5(5 + 7)*3 = 6*3 = 18 km2

Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2

Area of trapezoid: 0.5*(5+7)*3 = 18 square units

((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45

Area of a trapezoid measured in square units = 0.5*(sum of parallel sides)*height