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Q: Trapezoid has bases of 9 in and 7 in and height of 5 what is the area?
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A trapezoid has an area of 28ft2 The two bases are 5 ft and 9 ft What is the height of the trapezoid?

4 ft.


What is the area of a trapezoid if the meausure of the base is 8 and the height is 5?

Area of a trapezoid = 0.5*(sum of parallel bases)*height Need to know the measure of the other base


What is the height of a trapezoid with an area of 62.5 and the two bases as 11 and 14?

Height: (62.5*2)/25 = 5


A trapezoid has bases of 7 centimeters and 5 centimeters and a height of 3 centimeters What is its area?

The formula for area a is height X average of the two parallel bases of the trapezoid. In this instance, a = 3[(7 + 5)/2] = 18 square centimeters.


What is the area of a trapezoid if its bases are 12 and 18 meters long and its height is 4 meters?

the formula for the area of a trapezoid is one half the sum of its bases times the height. So, A = .5(b1+b2)h = .5(18+12)4 = 60 meters2


What is the height of a trapezoid that has an area of 65 and bases that equal 13?

The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.


What is the area of a trapezoid bases are 12Cm and 8Cm and the height is 5Cm?

1/2*(12+8)*5 = 50 square cm


What is the area of a trapezoid with bases 5 km 7 km and height 3 km?

It is 0.5(5 + 7)*3 = 6*3 = 18 km2


Find the area of a trapezoid with the bases of 6centimeters and 8centimeters with the height of 5centimeters?

Trapezoid Area = (1/2)(b1 + b2)(h) We have: b1 = 6cm b2 = 8 cm h = 5 cm Substitute the given values into the area formula: Trapezoid Area = (1/2)(b1 + b2)(h) Trapezoid Area = (1/2)(6 cm + 8 cm)(5 cm) Trapezoid Area = (1/2)(14 cm)(5 cm) Trapezoid Area = (7 cm)(5 cm) Trapezoid Area = 35 cm^2


Mateo graphs trapezoid JKLM which has a height of 3 units and bases of 5 units and 7 units. Mateo then reflects JKLM across the y-axis to create J'K'L'M'. What is the area of J'K'L'M' in square units?

Area of trapezoid: 0.5*(5+7)*3 = 18 square units


Find the area of isosceles trapezoid with height of 5 nonparallel sides of 6 and bases of 8 and 10?

((B+b)h)/2=area of a trapeziod B= larger base b=smaller base h=height ((10+8)5)/2= 45


What is the approximate area of a trapezoid with these dimensions 6 times 12 times 5 times 10 and a height that is 4?

Area of a trapezoid measured in square units = 0.5*(sum of parallel sides)*height