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The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5.

If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.

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7y ago
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11y ago

Don't look now, but if the bases are both the same, then

your figure is a rectangle. It's 13 long and 5 high.

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Q: What is the height of a trapezoid that has an area of 65 and bases that equal 13?
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