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β 13y agoYes you can. This is because a triangle can be solved by ASA (Angle Side Angle). To construct this first draw the side. Then put one angle on one end of the side and the other on the other end of the side. Then extend the lines on the angles until they intersect and the other sides and angle "just happen."
Wiki User
β 13y agoA+
90 degrees
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.
No, itβs false.
Where two straight lines cross the "vertically opposite" angles are equal.
Because Corresponding Parts of Congruent Triangles, there are five ways to prove that two triangles are congruent. Show that all sides are congruent. (SSS) Show that two sides and their common angle are congruent. (SAS) Show that two angles and their common side are congruent. (ASA) Show that two angles and one of the non common sides are congruent. (AAS) Show that the hypotenuse and one leg of a right triangle are congruent. (HL)
Not so. The two acute angles of a right triangle must add up to 90 degrees.So if the triangles have one congruent acute angle in common, they must alsohave the other acute angle in common, and then they're similar.
That two of the Angles are Supplementary and two of the Angles are congruent.
Their angles are the same.
False. Assume that you had a two right triangles with one congruent acute (<90 degrees) angle in common. Let x represent the number of degrees in this angle in both triangles (which we can do since the angles are congruent). Let y represent the degree of the other angle in the first triangle and let z represent the degree of the other angle in the second triangle. We know that the sum of the degrees of the angles in a triangle is 180. So for the first triangle we have, 90+x+y = 180 For the second triangle, 90+x+z=180 Therefore, 90+x+y=90+x+z Subtract the 90+x from each side: y=z Therefore the degrees of the angles of the two triangles both are 90 [because they are both right triangles], x [because we said that this is the number of degrees of the congruent angles given in the problem], and y [because y=z]. Because the three angles of both triangles have the same measurement, the triangles must be similar.
All their angles are less than 90 degrees.
A+
90 degrees
An angle is the intersection of two rays with a common endpoint. Adjacent Angles are 2 angles that share a common vertex, a common side and no common interior points.
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.
To verify that two triangles are similar, you can use several similarity postulates and theorems. The most common ones include: **AA Similarity Postulate (Angle-Angle Similarity Postulate):** If two angles of one triangle are congruent to two angles of another triangle, then the two triangles are similar. This postulate relies on the similarity of corresponding angles. **SAS Similarity Theorem (Side-Angle-Side Similarity Theorem):** If two pairs of corresponding sides of two triangles are in proportion, and their included angles are congruent, then the two triangles are similar. This theorem involves both sides and angles. **SSS Similarity Theorem (Side-Side-Side Similarity Theorem):** If the corresponding sides of two triangles are in proportion, then the two triangles are similar. This theorem only considers the proportions of the sides. These postulates and theorems are fundamental principles of triangle similarity and are used to establish whether two triangles are indeed similar. Remember that similarity means that the corresponding angles are equal, and the corresponding sides are in proportion.