Yes you can. This is because a triangle can be solved by ASA (Angle Side Angle). To construct this first draw the side. Then put one angle on one end of the side and the other on the other end of the side. Then extend the lines on the angles until they intersect and the other sides and angle "just happen."
90 degrees
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.
No, it’s false.
Having two dashes on a triangle is common notation in arithmetic, specifically geometry. Two dashes mean that there is one dash each on two different lines of the triangle, and this indicates that the two lines are of equal length. This also means that the triangle is an isosceles triangle.
Where two straight lines cross the "vertically opposite" angles are equal.
Isosceles triangles have congruent base angles, meaning the angles opposite the equal sides are the same. Additionally, certain polygons, such as isosceles trapezoids, also have congruent base angles. In general, any shape with symmetrical properties may exhibit congruent angles, but isosceles triangles and isosceles trapezoids are the most common examples.
Because Corresponding Parts of Congruent Triangles, there are five ways to prove that two triangles are congruent. Show that all sides are congruent. (SSS) Show that two sides and their common angle are congruent. (SAS) Show that two angles and their common side are congruent. (ASA) Show that two angles and one of the non common sides are congruent. (AAS) Show that the hypotenuse and one leg of a right triangle are congruent. (HL)
Not so. The two acute angles of a right triangle must add up to 90 degrees.So if the triangles have one congruent acute angle in common, they must alsohave the other acute angle in common, and then they're similar.
Two triangles are congruent when they have the same shape and size, meaning all corresponding sides and angles are equal. The most common criteria for establishing congruence are Side-Side-Side (SSS), Side-Angle-Side (SAS), Angle-Side-Angle (ASA), Angle-Angle-Side (AAS), and Hypotenuse-Leg (HL) for right triangles. If any of these conditions are met, the triangles can be considered congruent.
That two of the Angles are Supplementary and two of the Angles are congruent.
Their angles are the same.
False. Assume that you had a two right triangles with one congruent acute (<90 degrees) angle in common. Let x represent the number of degrees in this angle in both triangles (which we can do since the angles are congruent). Let y represent the degree of the other angle in the first triangle and let z represent the degree of the other angle in the second triangle. We know that the sum of the degrees of the angles in a triangle is 180. So for the first triangle we have, 90+x+y = 180 For the second triangle, 90+x+z=180 Therefore, 90+x+y=90+x+z Subtract the 90+x from each side: y=z Therefore the degrees of the angles of the two triangles both are 90 [because they are both right triangles], x [because we said that this is the number of degrees of the congruent angles given in the problem], and y [because y=z]. Because the three angles of both triangles have the same measurement, the triangles must be similar.
All their angles are less than 90 degrees.
90 degrees
An angle is the intersection of two rays with a common endpoint. Adjacent Angles are 2 angles that share a common vertex, a common side and no common interior points.
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.
No. A rhombus has all four sides of equal length. To split a rhombus into only 2 triangles, it must be split along a diagonal; which means that 2 of the sides of one of the triangles must be the same length as the sides of the rhombus, which being equal mean the triangles must be (at least) isosceles - scalene triangles will not work. Further, as the diagonal will be a common length to each of the triangles (the length of their third sides), it will form the base (ie the side opposite the vertex between the sides of equal length) of the isosceles triangles, and so the triangles must be to congruent isosceles triangles. If the diagonal has the same length as the side of the rhombus, then the two congruent triangles will be congruent equilateral triangles.