Let h and w equal the dimensions of the rectangle and A equal its area 2h + 2w = 30 The perimeter of the rectangle is the sum of its sides, two widths and two heights h*w = A The formula for the area of a rectangle We have two equations but three unknown variables. Without more information about this rectangle, it is impossible to solve for the area from the perimeter alone unless this rectangle was specified as being a square (which gives us a third equation, b = h )
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
5
the answer to number 20 is B...12
we know,area of rectangle = l * b perimeter= 45*30=1350 cm ^2
Yes if its dimensions were 3 cm and 12 cm.
w 20; l 30
Let h and w equal the dimensions of the rectangle and A equal its area 2h + 2w = 30 The perimeter of the rectangle is the sum of its sides, two widths and two heights h*w = A The formula for the area of a rectangle We have two equations but three unknown variables. Without more information about this rectangle, it is impossible to solve for the area from the perimeter alone unless this rectangle was specified as being a square (which gives us a third equation, b = h )
900
30
4 feet
4 feet
Write two simultaneous equations and solve them. One for the perimeter, one for the area.
Area: 54 square cm Perimeter: 30 cm
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
5
6x5