There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.
Let's denote the two integers as x and y. We know that x + y = -9 and x - y = 5. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations eliminates the y variable, giving us 2x = -4. Therefore, x = -2. Substituting x = -2 back into the first equation gives us y = -7. Thus, the two integers are -2 and -7.
shown on graphs . 3 types : translation , rotaation , reflection x , y - -x ,y = reflection over y axis x,y- y,-x = reflection over x- axis translation= x,y - x+ or - horizontal change , y+ or - vertical change Perfect reflection= x,y - y,-x 180 degree rotation = x,y - -x , -y 90 degree clockwise rotation=x,y - y , -x 90 degree counter clockwise rotation = x,y - -y,x when graphing transformations , label the new image points as primes . When theres more then one prime , up the amount. Ex: A(1,0) becomes A'(A prime) (-1,0) hope this helps!
Set x=0, solve for y, which is the y intercept: 0 - 3y = 9 --> y = -3. Set y=0 and solve for x = 9 for x-intercept.
x - 9y = 18At the x-intercept, y=0 :x = 18At the y-intercept, x=0 :-9y = 18-y = 2y = -2
Let x and y be two integers. x - y = x + (-y)
Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!
The set of integers is closed under addition so that if x and y are integers, then x + y is an integer.Addition of integers is commutative, that is x + y = y + xAddition of integers is associative, that is (x + y) + z = x + (y + z) and so, without ambiguity, either can be written as x + y + z.The same three rules apply to addition of rational numbers.
The set of integers is closed under addition so that if x and y are integers, then x + y is an integer.Addition of integers is commutative, that is x + y = y + xAddition of integers is associative, that is (x + y) + z = x + (y + z) and so, without ambiguity, either can be written as x + y + z.The same three rules apply to addition of rational numbers.
x + y = 41, where x and y are unknown integers.
Suppose the two integers are x and y and that y < xThen x - y less than x and also less than y implies that 0 < y < x < 2y.
Yes it is.
If both x and y are integers, then x plus y is always an integer, otherwise not.
x+y = 2 x-y = 8 +y and -y gets canceled that gives, 2x = 10 x = 5 substituting the value of x x+y = 2 5+y = 2 y =-3 hence the two integers are: x = 5 and y = -3
4
Well, there are two possible answers to this. Using the info you gave, you can set up two equations, using "x" and "y" to represent your integers: x - y = 7 (i.e., the two integers are 7 apart) and 1/2y + 1 = x Substituting for x in the first equation and solving for y gives you the pair x = -5 and y = -12. However, if you use 1/2x + 1 = y for your second equation, you get x = 16 and y = 9.
There are an infinite number of positive integers that satisfy the equation x^4 + y < 70.