That will depend on the triples of which none have been given but in order to be a Pythagorean triple they must comply with Pythagoras' theorem for a right angle triangle.
Yes
You can use pythagorean theorem twice to find the diagonal of a cube
The set of Pythagorean triple is three dimensional and infinitely large.
Yes because the given dimensions concur with Pythagoras' theorem for right angle triangles.
No, the multiple of any random triple is not a Pythagorean triple.
Nearly but not quite a Pythagorean triple
If you mean 3, 4 and 5 then yes it is a Pythagorean triple
What is the value of x if (13, 84, x) is a Pythagorean triple?
If p and q are integers, then a = p2 - q2 b = 2pq, and c = p2 + q2 form a Pythagorean triple. Furthermore, if p and q are co-prime then the triple is primitive Pythagorean.
A Pythagorean triple is three positive integers a, b, and c, such that a^2 + b^2 = c^2. A well known Pythagorean triplet is (3,4,5). If (a, b, c) is a Pythagorean triplet, then so is (ka, kb, kc) for any positive integer k.
34
No.
No
Let's try it out: 152 + 362 = 392 225 + 1296 = 1521 1521 = 1521 That is a pythagorean triple.
The triple is: 20, 21 and 29
That will depend on the triples of which none have been given but in order to be a Pythagorean triple they must comply with Pythagoras' theorem for a right angle triangle.