C = 2πr = 100 m
r = 100/(2π) = 50/π
A = πr^2 = π(50/π)^2 = 2500/π m^3 ≈ 795.775 m^3
625 square feet.. the area would be a square rectangle with 25 feet of fencing on each side.
Circumference=2pir=2x3.1416x30 ft=188ft Length of each side = circumference/4=188 ft/4=47 ft Answer: 47 feet
50' x 50'and its spelled dimension not demension
Assuming a rectangular plot, the perimeter is 2(Length + Width) = 2*(256 + 178) = 2*434 = 868 ft.
3,734 feet of fencing.
How much fencing is required to enclose a circular garden with a radius of 14 meters? (Use 3.14 for π) _
i need help
Approx. 408.4 feet.
50 pi meters
Fencing needed: 2*pi*18 = just over 113 meters
If the acreage is a square, you'll need 6,467 feet of fencing to enclose the area.
100 x 100
1 yd=3 ft. 16 yd= 48 ft. 294 - 48 = 246. 246 < 250, so the answer is NO.
barbwire
2*pi*radius or pi*diameter
Barbed wire was a type of fencing that enabled farmers to enclose land on the treeless plains. It was cost-effective and easy to install, allowing for the effective enclosure of large areas of land.
The circumference of a rectangle is 2*(length+width), so 2*(18+23) = 2*(41) = 82 Therefore, 82 feet of fencing is required to enclose the garden.