625 square feet.. the area would be a square rectangle with 25 feet of Fencing on each side.
50' x 50'and its spelled dimension not demension
Assuming a rectangular plot, the perimeter is 2(Length + Width) = 2*(256 + 178) = 2*434 = 868 ft.
2400 square meters
width=x length=y 2y + 2x = 22 y= 2x+2 2(2x+2) + 2x= 22 4x + 4 +2x = 22 6x=18 x=3 y=2(3) + 2 y=8 Length=8 Width=3
Double the 46 feet and 34 feet and add them together. This will give the perimeter of the rectangle in feet. Divide this number by 3 (3 ft in 1 yd) = to convert to yards.46 x 2 = 9234 x 2 = 6892 + 68 = 160 ft160 / 3 = 53.33Therefore 53.5 yards (rounded up). Fifty-three and a half yards.
That would probably be a 25x25 square with an area of 625 square feet.
50' x 50'and its spelled dimension not demension
36
832 yards
18 meters of fencing. You simply need to find the circumference of the rectangle.
I got no clue.
If the acreage is a square, you'll need 6,467 feet of fencing to enclose the area.
A square 14 ft on a side.
100 x 100
How much fencing is required to enclose a circular garden with a radius of 14 meters? (Use 3.14 for π) _
1 yd=3 ft. 16 yd= 48 ft. 294 - 48 = 246. 246 < 250, so the answer is NO.
Assuming a rectangular plot, the perimeter is 2(Length + Width) = 2*(256 + 178) = 2*434 = 868 ft.