A quadrilateral is a parallelogram if and only if its diagonals bisect each other (this should be in any geometry book)
Each diagonal of a rhombus would never bisect a pair of opposite angles, but the diagonals are perpendicular to each other
Square, rectangle, rhombus A.K.A. diamond, parallelogram (Maybe there's more, but these are what I can recall)
Yes, they do. Also, they are congruent to each other. * * * * * They do bisect each other but they are not congruent.
The diagonals of a square are congruent, bisect each other, perpendicular, and either diagonal's length is sqrt(2) times any side length.
Yes, in the figure of a kite one diagonal bisects the other. They do not bisect each other.
No, they do not. Only the longer diagonal bisects the shorter diagonal.
A parallelogram a rectangle a square and a rhombus
A quadrilateral is a parallelogram if and only if its diagonals bisect each other (this should be in any geometry book)
They bisect each other at 90 degrees. They are the perpendicular bisectors of each other.
2 diagonals bisect each other only in the case of square , parallelogram, rhombus , rectangle and isosceles trapezium ;not in ordinary quadrilaterals.
In most shapes the diagonals do not bisect one another. It might be possible to answer the question if it were more specific. To start with, shapes with how many sides?
Each diagonal of a rhombus would never bisect a pair of opposite angles, but the diagonals are perpendicular to each other
Yes. The diagonals of any parallelogram bisect each other. A rectangle is a special case of a parallelogram.
A square has 2 diagonals that are equal in length and bisect each other at right angles.
isn't it a rhombus ? the ones that are like a slanted square ? because there are no right angles but each diagonal bisects the corners.
The diagonals of a kite are perpendicular and therefore bisect each other at 90 degrees