Yes its 2 diagonal intersect at right angles
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
A rhombus is a two dimensional (plane) shape that is bounded by four congruent lines. If these lines meet at right angles, then the shape is a square which is a special type of rhombus.
Yes its 2 diagonal intersect at right angles
Not always, sometimes they are perpendicular.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
Yes they do,because if both diagonal lines cross over and perform a cross is were the point in the middle meets.
A rhombus is a two dimensional (plane) shape that is bounded by four congruent lines. If these lines meet at right angles, then the shape is a square which is a special type of rhombus.
Yes.
The main difference between a square and a rhombus is that a square has all its angles equal to 90 degrees and a rhombus does not. A square has 4 lines of symmetry while rhombus only has 2. The diagonal lengths of a square are of the same measure. Rhombus diagonal lengths are of different measures. They are both a quadrilateral, all sides are equal in length, and opposite sides are parallel to each other.
Yes.Yes.Yes.Yes.
Yes. In a rhombus (and in a square), the opposite angles that each diagonal connects are bisected by the diagonal.
isn't it a rhombus ? the ones that are like a slanted square ? because there are no right angles but each diagonal bisects the corners.