9 radical din 2
sqrt(162) = 9*sqrt(2)
2
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
A Huge ASS
If we factor 60, we get 60 = 2 * 2 * 3 * 5 So sqrt ( 60 ) = sqrt (2 * 2 * 3 * 5) = sqrt (2 * 2) * sqrt (3 * 5) = 4 * sqrt( 15 ) ____________________________________________________________ actually if you do by just using the simpler way you should get 2 radical 15 since , 60 has the closest perfect square of 4 and non perfect of 15 this is how you should solve radical 60 = radical 4 times radical 15 radical 60 = simplify the 4 to 2 and leave radical 15 So , radical 60 = 2 radical 15 not what is above .
9*radical(3)/2 = 4.5*radical(3) = 7.794 approx.
√2 x √2 = (√2)2 = 2
3
Ahh ok radical 40 is equal to 2 radical 10
2 radical 30
40
first the two numbers have the same radicand which is radical 2 so we just add the numbers before them to become 7 radical 2
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
5sqet(2) + sqrt(18) NB sqrt(18) = sqrt(2 x 9) = sqrt(2)Sqrt(9) = 3sqrt(2) Hence 5 sqrt(2) + 3sqrt(2) = 8sqrt(2)
sqrt(162) = 9*sqrt(2)
factor the 18. 18=2x3x3. Take out the 3 because it is squared. 5x3 radical 2=15radical2
2/3 = sqrt( 4/9 )