3root(6)+5root(2) you really answered it yourself!
2 + 3 + 4 = 9
yes if you are doing it this way: 3+2=2+3
factor the 18. 18=2x3x3. Take out the 3 because it is squared. 5x3 radical 2=15radical2
2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7
2 radical 30
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
√3 + √3 = 2√3
3
9 radical din 2
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
radical 3 or 6
-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
3root(6)+5root(2) you really answered it yourself!
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30