The description given fits that of a cylinder
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cylinder: 3 faces, 2 edges, no vertex
Yes. to add to that a vertex must be connected to at least 3 edges to be 3d, an edge is always connected to 2 vertexes, so the closest the two can ever be is vetexes x 3 = edges x 2, but when working with any platonic solid you can follow this: vertexes x (faces / vertexes) x [edges on one side] = edges x 2 or vertexes x [faces meeting at one vertex] = edges x 2 when working with any other polyhedron [vertexes with x amount of faces] x (x) + [vertexes with y amount of faces] x (y) ...{and so on} = edges x 2
A box, also known as a rectangular prism, has 6 faces, 12 edges, and 8 vertices. The faces of a box are all rectangles, with 3 pairs of congruent faces. The edges are where the faces meet, and there are 4 edges meeting at each vertex.
3 faces and 0 edges
An icosahedron has 20 faces, 30 edges, and 12 vertexes. 5 polygons meet at each vertex and each face has 3 vertexes (therefore made of triangles). A dodecahedron has 12 faces, 30 edges, and 20 vertexes. 3 polygons meet at each vertex and each face has 5 vertexes (therefore made of pentagons).
cylinder: 3 faces, 2 edges, no vertex
A cylinder does not have vertex but it has two circular edges and 3 faces
No such shape exists. The closest contenders would be: a cylinder - 3 faces, 2 edges, 0 verticies or a cone - 2 faces, 1 edge, 1 vertex
No such shape exists. The closest contenders would be: a cylinder - 3 faces, 2 edges, 0 verticies or a cone - 2 faces, 1 edge, 1 vertex
No such shape exists. the closest contenders would be: a cylinder - 3 faces, 2 edges, 0 verticies or a cone - 2 faces, 1 edge, 1 vertex
Tetrahedron 3 triangles meet at each vertex 4 Faces 4 Vertices 6 Edges Cube 3 squares meet at each vertex 6 Faces 8 Vertices 12 Edges Octahedron 4 triangles meet at each vertex 8 Faces 6 Vertices 12 Edges Dodecahedron 3 pentagons meet at each vertex 12 Faces 20 Vertices 30 Edges Icosahedron 5 triangles meet at each vertex 20 Faces 12 Vertices 30 Edges
As the name implies, there are 12 faces on a dodecahedron. Each face is a pentagon, which has 5 edges, so there would be 60 edges altogether except that each edge is shared by 2 faces, so there are 30 edges. Using Euler's formula V + F = E + 2, the number of vertices is 20. Therefore each vertex is shared by 3 faces and 3 edges.
no edges but 3 faces.
Yes. to add to that a vertex must be connected to at least 3 edges to be 3d, an edge is always connected to 2 vertexes, so the closest the two can ever be is vetexes x 3 = edges x 2, but when working with any platonic solid you can follow this: vertexes x (faces / vertexes) x [edges on one side] = edges x 2 or vertexes x [faces meeting at one vertex] = edges x 2 when working with any other polyhedron [vertexes with x amount of faces] x (x) + [vertexes with y amount of faces] x (y) ...{and so on} = edges x 2
4 faces (1 base +3 faces that converge) 4 vertices (3 vertices on the base + one which the 3 faces converge on) 6 edges (3 edges for the base + 3 edges leading to top vertex)
Yes, it has 2 edges and 3 faces
A rectangular prism has 6 faces and 8 vertexes . i hope you like my answer <3