ok
41
It is: 180-42 = 138 degrees
8.57 degrees
The 42 interior angles of a regular 42-agon add up to 7200 degrees and each angle is 7200/42 which is 171.'428571' degrees recurring decimal '428571'
The third angle measures 18 degrees.
180 - twice 42
41
90 - 42 ie 48o
It is: 180-42 = 138 degrees
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
To find the measure of angle 5, we can use the relationship between the arcs and the angles they subtend. If angle 5 subtends arc BC, then the measure of angle 5 is half the measure of arc BC. Therefore, angle 5 would measure ( \frac{42}{2} = 21 ) degrees. If angle 5 relates to arc DE, further information is needed to determine its measure.
69 degrees 180-42 = 138 138/2 = 69 degrees You do not need the measure of the side to derive the answer.
8.57 degrees
42
To find the measure of angle HLJ, we can use the fact that the sum of the angles in triangle HLI must equal 180 degrees. Therefore, angle HLJ can be calculated as follows: Angle HLJ = 180° - (angle ILJ + angle HLI) = 180° - (42° + 45°) = 180° - 87° = 93°. Thus, the measure of angle HLJ is 93 degrees.
Each interior angle measures 1710 25' 42.86''
171.428571 degrees (recurring decimal)